Question

1)3x-1-(x+3)=1 2)-10x=8 3)5(2y-4)=2(5y-10) 4)(8-x)(x+2)=0 5)(3x-2)(x+4)=0

Answer 1

Ответ: 1) 2,5; 2) -0,8; 3) 2; 4) -2 и 8; 5) 2/3 и -34/6.
Возможны ошибки.

Answer 2

Sure, I can help you solve these equations:

1. 3x - 1 - (x + 3) = 1

First, simplify the equation by combining like terms:

3x - 1 - x - 3 = 1

Now, combine the constants and the x terms:

(3x - x) - 1 - 3 = 1

2x - 4 = 1

Add 4 to both sides to isolate the x term:

2x - 4 + 4 = 1 + 4

2x = 5

Now, divide both sides by 2 to solve for x:

2x / 2 = 5 / 2

x = 5/2

So, the solution is x = 5/2.

2. -10x = 8

To solve for x, divide both sides by -10:

(-10x) / (-10) = 8 / (-10)

x = -8/10

Simplify the fraction:

x = -4/5

So, the solution is x = -4/5.

3. 5(2y - 4) = 2(5y - 10)

First, distribute the constants on both sides of the equation:

10y - 20 = 10y - 20

Notice that the variables cancel out, and you are left with:

-20 = -20

This equation is an identity, which means that it's true for all values of y. There is no specific solution for y because the equation is always true.

4. (8 - x)(x + 2) = 0

To solve for x, set each factor equal to zero and solve for x separately:

8 - x = 0

Subtract 8 from both sides:

-x = -8

Multiply both sides by -1 to isolate x:

x = 8

Now, for the second factor:

x + 2 = 0

Subtract 2 from both sides:

x = -2

So, there are two solutions: x = 8 and x = -2.

5. (3x - 2)(x + 4) = 0

To solve for x, set each factor equal to zero and solve for x separately:

3x - 2 = 0

Add 2 to both sides:

3x = 2

Divide both sides by 3:

x = 2/3

Now, for the second factor:

x + 4 = 0

Subtract 4 from both sides:

x = -4

So, there are two solutions: x = 2/3 and x = -4.