Question

11. 1) 7(2a + 1)² - (3a − 2)(6 - 2α) 2) - (3a − 1)² - (4 - 5a)(7 - 2a) - 5a²;​

Answer 1

Ответ:

Объяснение:

1) 7(2a + 1)² - (3a − 2)(6 - 2α)=28а²+28а+7-18а+6а²+12-4а=34а²+6а+19

2) - (3a − 1)² - (4 - 5a)(7 - 2a) - 5a²=-9а²+6а-1-28+8а+35а-10а²-5а²=-24а²+49а-29

Answer 2

Let's simplify the given expressions step by step:

1. $7(2a + 1)^2 - (3a - 2)(6 - 2a)$:

First, expand the squares:

$7(4a^2 + 4a + 1) - (3a - 2)(6 - 2a)$

Now, distribute the 7 and simplify:

$28a^2 + 28a + 7 - (3a - 2)(6 - 2a)$

Now, distribute the -(3a - 2) on the right side:

$28a^2 + 28a + 7 - (18 - 6a - 12a + 4a^2)$

Now, simplify further:

$28a^2 + 28a + 7 - 18 + 6a + 12a - 4a^2$

Combine like terms:

$28a^2 - 4a^2 + 28a + 6a + 12a + 7 - 18$

$24a^2 + 46a - 11$

So, the simplified expression is $24a^2 + 46a - 11$.

2. $-(3a - 1)^2 - (4 - 5a)(7 - 2a) - 5a^2$:

First, expand the square:

$-(9a^2 - 6a + 1) - (4 - 5a)(7 - 2a) - 5a^2$

Now, distribute the negative sign:

$-9a^2 + 6a - 1 - (4 - 5a)(7 - 2a) - 5a^2$

Now, multiply the binomials (4 - 5a) and (7 - 2a):

$-9a^2 + 6a - 1 - (28 - 12a - 35a + 10a^2) - 5a^2$

Now, simplify further:

$-9a^2 + 6a - 1 - 28 + 12a + 35a - 10a^2 - 5a^2$

Combine like terms:

$-9a^2 - 10a^2 + 6a + 12a + 35a - 1 - 28$

$-19a^2 + 53a - 29$

So, the simplified expression is $-19a^2 + 53a - 29$.