Question

Решите уравнения: (4+9b)^2+(9b+2)(2-9b)=0 (3/4-5d)(5d+3/4)+(5d-3/4)^2=0

Answer 1

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Готово!!Удачи))

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Answer 2

16+72b+81b²+(2+9b)(2-9b)=0

16+72b+81b²+4-81b²=0

20+72b=0

72b=-20

b= -5/18 или - 0,27

(3/4-5d)(3/4+5d)+25d²-15/2d+9/16=0

9/16-25d²+25d²-15/2d+9/16=0

9/8-15/2d=0

9-60d=0

-60d= -9

d= 3/20 или 0,15

Answer 3

To solve the equations, we need to find the values of 'b' and 'd' that satisfy each equation. Let's solve them one by one:

1. (4+9b)^2 + (9b+2)(2-9b) = 0

First, let's expand the equation:

(4+9b)^2 + (9b+2)(2-9b) = (4+9b)(4+9b) + (9b+2)(2-9b) = 16 + 36b + 36b + 81b^2 + 18 - 81b^2 = 34b + 34

Now, set the equation equal to zero and solve for 'b':

34b + 34 = 0 34b = -34 b = -34/34 b = -1

So, the solution for the first equation is b = -1.

2. (3/4 - 5d)(5d + 3/4) + (5d - 3/4)^2 = 0

First, let's expand the equation:

(3/4 - 5d)(5d + 3/4) + (5d - 3/4)^2 = (15d^2 + (3/4) * 5d - (5d * 3/4) - (3/4)^2) + (25d^2 - (3/4) * 5d - (5d * 3/4) + (3/4)^2) = 15d^2 + (15/4)d - (15/4)d + 9/16 + 25d^2 - (15/4)d - (15/4)d + 9/16 = 40d^2 + 9/8

Now, set the equation equal to zero and solve for 'd':

40d^2 + 9/8 = 0 40d^2 = -9/8 d^2 = -(9/8) / 40 d^2 = -9 / (8 * 40) d^2 = -9 / 320

Since we have a negative value on the right side, there are no real solutions for 'd' in this equation.

So, the solution for the second equation is "No real solutions".