Question

1)(b⁴)⁶×(b⁵)⁴; 2)(b¹⁶)⁴:(b³)²⁰;3)(b⁹)¹²:(b¹⁰)¹⁰;4)(b³⁰):(b⁴)²⁰;5)(b³)⁷×(b⁵)⁵;6)(b⁷)⁶:(b⁸)⁵.​

Answer 1

Ответ:

решение смотри на фотографии

Объяснение:

Answer 2

To simplify these expressions with the same base variable "b," you can apply the rules of exponents:

1. (b^4)^6 × (b^5)^4 = b^(46) × b^(54) (Use the rule (a^m)^n = a^(m*n)) = b^24 × b^20 = b^(24+20) (Use the rule a^m × a^n = a^(m+n)) = b^44

2. (b^16)^4 ÷ (b^3)^20 = b^(164) ÷ b^(320) = b^64 ÷ b^60 = b^(64-60) (Use the rule a^m ÷ a^n = a^(m-n)) = b^4

3. (b^9)^12 ÷ (b^10)^10 = b^(912) ÷ b^(1010) = b^108 ÷ b^100 = b^(108-100) = b^8

4. (b^30) ÷ (b^4)^20 = b^30 ÷ b^(4*20) = b^30 ÷ b^80 = b^(30-80) = b^(-50)

5. (b^3)^7 × (b^5)^5 = b^(37) × b^(55) = b^21 × b^25 = b^(21+25) = b^46

6. (b^7)^6 ÷ (b^8)^5 = b^(76) ÷ b^(85) = b^42 ÷ b^40 = b^(42-40) = b^2

So, the simplified expressions are:

1. b^44
2. b^4
3. b^8
4. b^(-50)
5. b^46
6. b^2