Question

1) 0,6x2y· (-0,5x5y7) 2) 0,6x4 ·(-10x4) 3 3) (2a7x12) 4 · ax 4) (3a2 - 11a + 4) – (6a2 - 2a - 3) 5) 3a3 ·(2a2 - 4) 6) (x + 1) (x2 - 3x - 4) 7) (x + 5) (2 x2 - 2) -10x2 ​

Answer 1

Ответ:

Объяснение:

1. 0,6x2y * (-0,5x5y7) = 1,2xy * (-17,5xy) = 21x^2 y^2
2. 0,6x4 * (-10x4)3 = 2,4x * (-40x) 3 = -288 x^2
3. (2a7x12)4 * ax = 168ax * 4ax = 672a^2 x^2
4. (3a2 - 11a + 4) - (6a2 - 2a - 3) = (6a - 11a + 4) - (12a - 2a - 3) = (-5a + 4) - (10a - 3) = -5a + 4 - 10a + 3 = -15a + 7
5. 3a3 * (2a2 - 4) = 9a * (4a - 4) - 36a^2 - 36s
6. (x + 1) (x2 - 3x - 4) = (x + 1) (-x - 4) = -(x+1) (x+4) = -(x^2 + 5x + 4) = -x^2 - 5x - 4
7. (x+5) (2x2 - 2) - 10x2 = (x+5) (4x-2) - 20x = 4x^2 - 18x - 10 - 20x =  4x^2 - 38x - 10

Answer 2

Let's simplify each expression step by step:

1. $0.6x^2y \cdot (-0.5x^5y^7)$ = $0.6 \cdot (-0.5) \cdot x^{2+5} \cdot y^{1+7}$ = $-0.3x^7y^8$

2. $0.6x^4 \cdot (-10x^4)$ = $0.6 \cdot (-10) \cdot x^{4+4}$ = $-6x^8$

3. $(2a^7x^12)^4 \cdot ax$ = $2^4 \cdot a^{7 \cdot 4} \cdot x^{12 \cdot 4} \cdot ax$ = $16a^{28}x^{48}ax$ = $16a^{29}x^{48}$

4. $(3a^2 - 11a + 4) - (6a^2 - 2a - 3)$ = $3a^2 - 11a + 4 - 6a^2 + 2a + 3$ = $-3a^2 - 9a + 7$

5. $3a^3 \cdot (2a^2 - 4)$ = $3a^3 \cdot 2a^2 - 3a^3 \cdot 4$ = $6a^5 - 12a^3$

6. $(x + 1) \cdot (x^2 - 3x - 4)$ = $x(x^2 - 3x - 4) + 1(x^2 - 3x - 4)$ = $x^3 - 3x^2 - 4x + x^2 - 3x - 4$ = $x^3 - 2x^2 - 7x - 4$

7. $(x + 5) \cdot (2x^2 - 2) - 10x^2$ = $2x^3 + 10x^2 - 2x + 10x^2 - 10x^2$ = $2x^3 - 2x$

These are the simplified forms of the given expressions.