Question

2) 0,6x4 (-10x4) 3 3) (2a7x12) 4 ax 4) (3a2 - 11a + 4) – (6a2 - 2a - 3) 5) 7a4 (3a2 +12) 6) (x + 1) (x2 – х + 1) 7) (x + 5) (2 x2 - 2) -10x2 8) (8a4 + 2a3) : a3

Answer 1

Ответ:

Photomath

Объяснение:

Там фоткаешь и всё

Answer 2

Let's solve each of the given expressions step by step:

1. 0.6 * 4 - (10 * 4) / 3 = 2.4 - 40 / 3 To subtract the fractions, find a common denominator, which is 3. = (7.2 - 40) / 3 = (-32.8) / 3 ≈ -10.93 (rounded to two decimal places)

2. (2a^7 * 12) / (4a) = (24a^7) / (4a) To simplify, divide both the coefficients and subtract the exponents: = (24/4) * (a^7/a^1) = 6 * a^(7-1) = 6a^6

3. (3a^2 - 11a + 4) - (6a^2 - 2a - 3) = 3a^2 - 11a + 4 - 6a^2 + 2a + 3 = (3a^2 - 6a^2) + (-11a + 2a) + (4 + 3) = -3a^2 - 9a + 7

4. 7a^4 * (3a^2 + 12) = 7a^4 * 3a^2 + 7a^4 * 12 = 21a^6 + 84a^4

5. (x + 1) * (x^2 - x + 1) This is a multiplication of two binomials, which can be expanded using FOIL (First, Outer, Inner, Last): = x(x^2 - x + 1) + 1(x^2 - x + 1) = x^3 - x^2 + x + x^2 - x + 1 = x^3 + 1

6. (x + 5) * (2x^2 - 2) - 10x^2 This is also a multiplication of two binomials: = x(2x^2 - 2) + 5(2x^2 - 2) - 10x^2 = 2x^3 - 2x + 10x^2 - 10 - 10x^2 = 2x^3 - 2

7. (8a^4 + 2a^3) / a^3 To simplify, divide each term by a^3: = (8a^4 / a^3) + (2a^3 / a^3) = 8a^(4-3) + 2a^(3-3) = 8a + 2 = 2(4a + 1)

So, these are the simplified expressions for each of the given problems.