Question

Найдите координаты вершины параболы y = -0,2x^2+6x-16. Ответ: (? ; ?)

Answer 1

Ответ:

хв= -6/2*(-0,2)=15

ув= -0,2*15²+6*15-16=29

ответ:(15;29).

Answer 2

Finding the Coordinates of the Vertex of a Parabola

To find the coordinates of the vertex of the parabola given by the equation y = -0.2x^2 + 6x - 16, we can use the formula x = -b/2a to find the x-coordinate of the vertex.

In this case, the coefficient of x^2 is a = -0.2 and the coefficient of x is b = 6. Plugging these values into the formula, we get:

x = -6 / (2 * -0.2) = -6 / -0.4 = 15

Now, to find the y-coordinate of the vertex, we substitute the value of x back into the equation:

y = -0.2(15)^2 + 6(15) - 16 = -0.2(225) + 90 - 16 = -45 + 90 - 16 = 29

Therefore, the coordinates of the vertex of the parabola are (15, 29).