Question

A) 4x²-1=б) 1-9a²=в) m²-a²=г) -n²+a²=д)a²-16y²=​

Answer 1

Ответ:

а) 4х²-1=(2х-1)(2х+1)

б) 1-9а²=(1-3а)(1+3а)

в)m²-a²=(m-a)(m+a)

г)-n²+a²=a²-n²=(a-n)(a+n)

д) а²-16у²=(а-4у)(а+4у)

Объяснение:

используем формулу а²+b²=(a-b)(a+b)

Answer 2

Формула сокращенного умножения разность квадратов

a^2-b^2=(a-b)(a+b)

a)4x²-1=(2x-1)(2x+1)

б) 1-9a²=(1-3a)(1+3a)

в) m²-a²=(m-a)(m+a)

г) -n²+a²=a^2-n^2=(a-n)(a+n)

д)a²-16y²=(a-4y)(a+4y)

Answer 3

It looks like you have provided a list of equations with different variables and expressions. To help you solve these equations, I'll provide solutions for each of them:

A) 4x² - 1 = 0: Add 1 to both sides: 4x² = 1 Divide by 4: x² = 1/4 Take the square root of both sides: x = ±√(1/4) x = ±1/2

So, the solutions for A) are x = 1/2 and x = -1/2.

B) 1 - 9a² = 0: Add 9a² to both sides: 9a² = 1 Divide by 9: a² = 1/9 Take the square root of both sides: a = ±√(1/9) a = ±1/3

So, the solutions for B) are a = 1/3 and a = -1/3.

C) m² - a² = 0: Factor the difference of squares: (m + a)(m - a) = 0 Set each factor equal to zero: m + a = 0 --> m = -a m - a = 0 --> m = a

So, the solutions for C) are m = -a and m = a.

D) -n² + a² = 0: Factor the difference of squares: (a + n)(a - n) = 0 Set each factor equal to zero: a + n = 0 --> n = -a a - n = 0 --> n = a

So, the solutions for D) are n = -a and n = a.

E) a² - 16y² = 0: Factor the difference of squares: (a + 4y)(a - 4y) = 0 Set each factor equal to zero: a + 4y = 0 --> a = -4y a - 4y = 0 --> a = 4y

So, the solutions for E) are a = -4y and a = 4y.

These are the solutions for each of the provided equations.