Question

25х²-(4х-1)² спасибо ​

Answer 1

25x²-(4x-1)²= (5x-4x+1)*(5x+4x-1)= (x+1)*(9x-1)

Answer 2

Разность квадратов

25х²-(4х-1)²=(5х)²-(4х-1)²=(5х-4х+1)(5х+4х-1)=(х+1)(9х-1).

Answer 3

You're welcome! It looks like you've provided an algebraic expression: 25x² - (4x - 1)². To simplify this expression, we need to expand the squared term:

(4x - 1)² = (4x - 1)(4x - 1) = 16x² - 8x + 1

Now, we can substitute this result back into the original expression and simplify further:

25x² - (4x - 1)² = 25x² - (16x² - 8x + 1)

To remove the parentheses, we need to distribute the negative sign:

25x² - (16x² - 8x + 1) = 25x² - 16x² + 8x - 1

Now, combine like terms:

(25x² - 16x²) + 8x - 1 = 9x² + 8x - 1

So, the simplified expression is 9x² + 8x - 1.