Question

Tg²45° + cos²45° ...​

Answer 1

$\displaystyle\bf\\tg^{2} 45^\circ+Cos^{2} 45^\circ=1^{2} +\Big(\frac{1}{\sqrt{2} } \Big)^{2} =1+\frac{1}{2} =1,5$

Answer 2

Tg²45° = tan(45°)² = 1² = 1 cos²45° = cos(45°)² = (sqrt(2)/2)² = 2/4 = 1/2

Таким образом, получаем: Tg²45° + cos²45° = 1 + 1/2 = 3/2