Question

Тіктөртбұрыштың периметрі 28см, ал диагонаоі 10 см. Тіктөртбұрыштың қабырғаларын теңдеулер жүйесін құрып табыңдар. 65 балл срочно​

Answer 1

Ответ:

P=28 d=10

Объяснение:

28+10•x=x2 x=28+10. x=38 x=x2:38. x=16x

Answer 2

I can help you with this question. The problem is to find the sides of a rectangle whose perimeter is 28 cm and diagonal is 10 cm. We can use the system of equations to solve this problem.

Let x and y be the sides of the rectangle. Then, we have the following equations:

x + y = 14 (from the perimeter formula P = 2(x + y))

x^2 + y^2 = 100 (from the Pythagorean theorem d^2 = x^2 + y^2)

We can solve this system by substitution. From the first equation, we can express y in terms of x:

y = 14 - x

Then, we can substitute this into the second equation and get:

x^2 + (14 - x)^2 = 100

Expanding and simplifying, we get:

2x^2 - 28x + 96 = 0

Dividing by 2, we get:

x^2 - 14x + 48 = 0

This is a quadratic equation that can be factored as:

(x - 6)(x - 8) = 0

Therefore, the possible values of x are 6 and 8. Correspondingly, the possible values of y are 8 and 6. This means that the rectangle is actually a square with sides of 6 cm or 8 cm.

We can check our answer by plugging these values into the original equations and see that they are satisfied.

Therefore, the sides of the rectangle are 6 cm and 8 cm.

I hope this helps you understand the solution. You can also find more information and examples on the web . Good luck with your homework!