Question

Используя формулы сокращенного умножения преобразуйте следующие выражения №1 (1,3p2+2,5q)2 = 1,3p2 + 2*1,3p*2,5q + 2,5q2 №2 (m+4)2-4(m+1)2 №3 (10m2-n2) (10m2+n2) №4 (y+6)2-(y+5)(y-5) №5 (3x+2y)3 №6 (5a+7b)2-70ab №7 (x+2y)(x2-2xy+4y2) №8 (5x2+2y3)(2y3-5x2) №9 (3x-2)(3x+2)-(1+x)(x-1) №10 (3a-2b)(9a2+6ab+4b2)

Answer 1

Объяснение:

.........................

Answer 2

№1: (1,3p^2 + 2,5q)^2 = (1,3p^2)^2 + 2 * (1,3p^2) * (2,5q) + (2,5q)^2 = 1,69p^4 + 6,5p^2q + 6,25q^2

№2: (m + 4)^2 - 4(m + 1)^2 = m^2 + 8m + 16 - 4(m^2 + 2m + 1) = m^2 + 8m + 16 - 4m^2 - 8m - 4 = -3m^2

№3: (10m^2 - n^2) + (10m^2 + n^2) = 10m^2 - n^2 + 10m^2 + n^2 = 20m^2

№4: (y + 6)^2 - (y + 5)(y - 5) = y^2 + 12y + 36 - (y^2 - 25) = y^2 + 12y + 36 - y^2 + 25 = 12y + 61

№5: (3x + 2y)^3 = (3x)^3 + 3 * (3x)^2 * (2y) + 3 * (3x) * (2y)^2 + (2y)^3 = 27x^3 + 54x^2y + 36xy^2 + 8y^3

№6: (5a + 7b)^2 - 70ab = (5a)^2 + 2 * (5a) * (7b) + (7b)^2 - 70ab = 25a^2 + 70ab + 49b^2 - 70ab = 25a^2 + 49b^2

№7: (x + 2y)(x^2 - 2xy + 4y^2) = x^3 + 2xy^2 - 2x^2y - 4xy^2 + 4y^3 = x^3 - 2x^2y + 2xy^2 + 4y^3

№8: (5x^2 + 2y^3)(2y^3 - 5x^2) = (5x^2)^2 - (2y^3)^2 = 25x^4 - 4y^6

№9: (3x - 2)(3x + 2) - (1 + x)(x - 1) = (3x)^2 - (2)^2 - (x + 1)(x - 1) = 9x^2 - 4 - (x^2 - 1) = 9x^2 - x^2 + 1 - 4 = 8x^2 - 3

№10: (3a - 2b)(9a^2 + 6ab + 4b^2) = (3a)^3 - (2b)^3 + 3 * (3a) * (9a^2 + 6ab + 4b^2) - 2b * (9a^2 + 6ab + 4b^2) = 27a^3 - 8b^3 + 81a^3 + 54a^2b + 36ab^2 - 18a^2b - 12ab^2 - 8b^3 = 108a^3 - 16b^3 + 63a^2b - 6ab^2