Question

 3x+2-6x+2)>0

Answer 1

Задание решено в двух вариантах, т.к. непонятно что делать с одной скобкой 3x+2-6x+2)>0
(36)

Answer 2

3х  +  2  -  6(х  +  2)  >  0
3x  +  2  -  6x  -  12       >  0
3x  <  -10
x  <  -10/3
x  <  -3 1/3
Ответ.    (-бесконечности;    -3 1/3)

Answer 3

To solve the inequality $3x + 2 - 6x + 2 > 0$, you need to simplify it and then find the values of $x$ that satisfy the inequality. Here's how you can do it:

1. Combine like terms on the left side of the inequality: $3x - 6x + 2 + 2 > 0$

2. Combine the $3x$ and $-6x$ terms: $-3x + 4 > 0$

3. Move the constant term (4) to the right side of the inequality by subtracting 4 from both sides: $-3x > -4$

4. Now, divide both sides by -3, but remember to reverse the inequality sign when dividing by a negative number: $x < \frac{-4}{-3}$

5. Simplify the right side: $x < \frac{4}{3}$

So, the solution to the inequality $3x + 2 - 6x + 2 > 0$ is $x < \frac{4}{3}$. This means that all values of $x$ less than $\frac{4}{3}$ will satisfy the inequality.