Question

(2x+3) (x²+y²-2xy)=0

Answer 1

Корень из первой скобки(—3/2), а вторая скобка это (х-у)^2=>х=у
Ответ: у и -3/2

Answer 2

To solve the equation (2x+3)(x²+y²-2xy) = 0, you can use the zero-product property, which states that if the product of two factors is equal to zero, then at least one of the factors must be equal to zero. So, you need to set each factor equal to zero and solve for x and y separately:

1. Set 2x + 3 = 0: 2x + 3 = 0 2x = -3 x = -3/2

2. Set x² + y² - 2xy = 0: x² + y² - 2xy = 0

This equation cannot be solved directly for x and y without additional information or constraints. It's a quadratic equation in two variables (x and y), and it represents a curve in the xy-plane. The solutions for x and y would depend on specific values or constraints for the equation.

So, one solution for x is x = -3/2, and the other solutions for x and y depend on the additional information or constraints provided for the equation.