
Решение систем уравнений: 3x+2y=-27 -5x+2y=13


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Вычтем из (1) второе уравнение
Из второго
Ответ:



To solve the system of equations:
- 3x + 2y = -27
- -5x + 2y = 13
We can use the method of elimination. The goal is to eliminate one of the variables (y, in this case) by adding or subtracting the equations. Let's proceed step by step:
Step 1: Multiply both sides of the second equation by 3 to make the coefficients of y in both equations equal:
2a. 3(-5x + 2y) = 3(13) 2b. -15x + 6y = 39
Now, the system becomes:
- 3x + 2y = -27
- -15x + 6y = 39
Step 2: Now, let's eliminate y by adding the modified equation 2b to equation 1:
(3x + 2y) + (-15x + 6y) = -27 + 39
Step 3: Simplify the equation:
-12x + 8y = 12
Step 4: Divide the entire equation by 4 to simplify it further:
(-12x + 8y)/4 = 12/4
Step 5: The equation becomes:
-3x + 2y = 3
Step 6: Now we have a new simplified equation. Let's solve for y:
2y = 3 + 3 2y = 6
Step 7: Divide both sides by 2 to find the value of y:
y = 6/2 y = 3
Step 8: Now that we have the value of y, we can substitute it back into either equation 1 or 2 to find the value of x. Let's use equation 1:
3x + 2(3) = -27
Step 9: Simplify the equation:
3x + 6 = -27
Step 10: Move 6 to the other side of the equation:
3x = -27 - 6 3x = -33
Step 11: Finally, divide both sides by 3 to find the value of x:
x = -33/3 x = -11
So, the solution to the system of equations is x = -11 and y = 3.


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