Question

Если 6-z=z-6 то 5(z^2-12z+36)/Z^3+2z^2-3z-4

Answer 1

Ответ:

0

Объяснение:

6 - z = z - 6

2z = 12

z = 6, значит (z - 6) = 0.

$\dfrac{5(z^2-12z+36)}{z^3+2z^2-3z-4}=\dfrac{5(z^2-2\cdot6z+(6)^2)}{z^3+2z^2-3z-4}=$

$=\dfrac{5(z-6)^2}{z^3+2z^2-3z-4}=\dfrac{0}{z^3+2z^2-3z-4}=0$

Применили формулу a² - 2ab + b² = (a - b)²

Answer 2

To solve the equation 6-z = z-6, we can follow these steps:

Step 1: Simplify the equation: 6 - z = z - 6

Step 2: Get all the z terms on one side of the equation: Add z to both sides: 6 = 2z - 6

Step 3: Isolate the z term on one side by moving the constant term to the other side: Add 6 to both sides: 12 = 2z

Step 4: Solve for z: Divide both sides by 2: z = 12/2 z = 6

Now, we have the value of z, which is 6.

Next, we need to evaluate the expression (5(z^2 - 12z + 36))/(z^3 + 2z^2 - 3z - 4) using the value of z we found.

Substitute z = 6 into the expression:

(5(6^2 - 12 * 6 + 36))/(6^3 + 2 * 6^2 - 3 * 6 - 4)

Simplify further:

(5(36 - 72 + 36))/(216 + 2 * 36 - 18 - 4)

(5(0))/(216 + 72 - 18 - 4)

(0)/(266 - 22)

0/244

The result of the expression is 0.