Question

Вычислите значение функции y=1/3x^2-8x+2/3 если аргумент x равен 1; -2; 3.

Answer 1

F(1)= -7; f(-2)= 18; f(3)= -20 1/3

Answer 2

To calculate the values of the function $y = \frac{1}{3}x^2 - 8x + \frac{2}{3}$ for the given arguments $x = 1$, $x = -2$, and $x = 3$, you simply need to substitute each value of $x$ into the expression and perform the arithmetic:

1. For $x = 1$: $y = \frac{1}{3}(1)^2 - 8(1) + \frac{2}{3} = \frac{1}{3} - 8 + \frac{2}{3} = -\frac{25}{3}$.

2. For $x = -2$: $y = \frac{1}{3}(-2)^2 - 8(-2) + \frac{2}{3} = \frac{1}{3}(4) + 16 + \frac{2}{3} = \frac{22}{3}$.

3. For $x = 3$: $y = \frac{1}{3}(3)^2 - 8(3) + \frac{2}{3} = \frac{1}{3}(9) - 24 + \frac{2}{3} = -\frac{19}{3}$.

So, the values of the function for $x = 1$, $x = -2$, and $x = 3$ are $-\frac{25}{3}$, $\frac{22}{3}$, and $-\frac{19}{3}$ respectively.