Question

При каких значениях a обращается в нуль: 1)a-3/4 2)a+3/a-3 3)a+0,1/3a-1 4)a(a-4)/a+15 5) (a+1)a+5)/a-3

Answer 1

1) 3/4

2) -3

3) -0,1

4) 4

5) -1;-5

Answer 2

To find the values of "a" at which each expression equals zero, we need to set each expression equal to zero and solve for "a." Let's solve them one by one:

1. $a - \frac{3}{4} = 0$ To solve for "a," add $\frac{3}{4}$ to both sides: $a = \frac{3}{4}$

2. $a + \frac{3}{a} - 3 = 0$ To solve for "a," move all terms to one side of the equation: $a^2 - 3a + 3 = 0$

Unfortunately, this equation doesn't have a simple solution using real numbers. It represents a quadratic equation, and its solutions will involve complex numbers.

3. $a + \frac{0.1}{3a} - 1 = 0$ To solve for "a," move all terms to one side of the equation: $3a^2 - 10a + 0.1 = 0$

This equation also requires the use of the quadratic formula or other methods to find the solutions.

4. $\frac{a(a - 4)}{a + 15} = 0$ To solve for "a," set the numerator equal to zero: $a(a - 4) = 0$

This equation has two solutions: $a = 0$ and $a = 4$.

5. $\frac{(a + 1)(a + 5)}{a - 3} = 0$ To solve for "a," set the numerator equal to zero: $(a + 1)(a + 5) = 0$

This equation has two solutions: $a = -1$ and $a = -5$.

In summary:

1. $a = \frac{3}{4}$
2. Complex solutions
3. Complex solutions
4. $a = 0$ and $a = 4$
5. $a = -1$ and $a = -5$