Question

Решите уравнение:2х2-50=0​

Answer 1

$2 {x}^{2} - 50 = 0 \\ 2x {}^{2} = 50 \\ x {}^{2} = 25 \\ x = + - 5$

вот так решается

Answer 2

To solve the quadratic equation 2x^2 - 50 = 0, you can use the quadratic formula, which is:

x = (-b ± √(b^2 - 4ac)) / 2a

In this equation, the coefficients are: a = 2 b = 0 (because there's no x term, so it's 0x) c = -50

Now, plug these values into the quadratic formula:

x = (-(0) ± √((0)^2 - 4 * 2 * (-50))) / (2 * 2)

Simplifying further:

x = ±√(0 + 400) / 4

x = ±√400 / 4

x = ±20 / 4

Now, calculate both roots:

1. x = (20) / 4 = 5
2. x = (-20) / 4 = -5

So, the solutions to the equation 2x^2 - 50 = 0 are x = 5 and x = -5.