Question

Log3(27/b^2) ,если log3 (b)=2​

Answer 1

Ответ:

Объяснение:

log3(27/b^2)=log3(27) - log3(b^2)=3-2log3(b)=3-2=1

Ответ:1

Answer 2

To solve the expression, we need to use the properties of logarithms. Since log3(b) = 2, we know that b = 3^2 = 9.

Now, we can substitute this value of b into the expression log3(27/b^2):

log3(27/b^2) = log3(27/9^2) = log3(27/81) = log3(1/3).

Remember that log3(1/3) is the exponent to which we need to raise 3 to get 1/3. Since 3^(log3(1/3)) = 1/3, the value of log3(1/3) is -1.

So, log3(27/b^2) = -1.