Question

{x+8y=-6 5x-2y=12 gjvjubnt ggg Смотреть ответ Участник Знаний Участник Знаний Готово Удачі))))))))))))

Answer 1

I see that you've provided a system of two linear equations:

1. x + 8y = -6
2. 5x - 2y = 12

To find the solution to this system of equations, we can use either the substitution method or the elimination method. Let's use the elimination method:

Step 1: Multiply both sides of Equation 1 by 5 and Equation 2 by 1 to make the coefficients of x in both equations equal:

5(x + 8y) = 5(-6) --> 5x + 40y = -30 1(5x - 2y) = 1(12) --> 5x - 2y = 12

Step 2: Now, we can subtract the modified Equation 2 from the modified Equation 1 to eliminate x:

(5x + 40y) - (5x - 2y) = -30 - 12 40y + 2y = -42 42y = -42 y = -42 / 42 y = -1

Step 3: Substitute the value of y (-1) back into any of the original equations (let's use Equation 1):

x + 8(-1) = -6 x - 8 = -6 x = -6 + 8 x = 2

So, the solution to the system of equations is x = 2 and y = -1.

I noticed some random text after your equations, but it doesn't seem to be related to the math problem. If you have any more questions or need further assistance, feel free to ask!