Question

Log2 48 - log2 3 + log3 1

Answer 1

Ответ:Log2 48 -Log2 3+Log3 1

Log2 16+Log 3 1

Log2 16+0

Log2(2)4

4

Объяснение:

Answer 2

To simplify the expression, let's use some logarithmic properties:

1. log_a(b) - log_a(c) = log_a(b/c)
2. log_a(b) + log_a(c) = log_a(b * c)
3. log_a(1) = 0

Using these properties, we can simplify the expression:

log2(48) - log2(3) + log3(1)

= log2(48/3) + log3(1)

= log2(16) + log3(1)

Now, log3(1) is 0 according to property 3 mentioned above.

= log2(16) + 0

Now, log2(16) is the exponent to which 2 must be raised to get 16. Since 2^4 = 16, log2(16) = 4.

= 4 + 0

Finally, the result is:

4