Question

1−g(2)−2gz−z(2) . Выбери правильный ответ: (1−g)⋅(1+g−2z) (g+z)2 (g−z)2 (1−g−z)⋅(1+g+z) (1−g)⋅(1+z)

Answer 1

Ответ:

(1 + g + z)(1 - g - z)

Объяснение:

1 - g² - 2gz - z² = 1 - (g² + 2gz + z²) = 1 - (g + z)² = (1 + g + z)(1 - g - z)

Answer 2

To simplify the expression, let's start by factoring it step by step:

1 - g(2) - 2gz - z(2)

Now, let's factor out common terms:

1 - 2gz - g(2) - z(2)

Next, let's rearrange the terms to group them accordingly:

(1 - 2gz) - (g(2) + z(2))

Now, we can factor each part:

(1 - 2gz) - (g^2 + z^2)

We recognize the expression (a^2 - b^2) as the difference of squares, which factors as (a + b)(a - b):

[(1 - 2gz) - (g^2 + z^2)] = [(1 - √2gz)(1 + √2gz)] - [(g + z)(g - z)]

The simplified expression is:

(1 - √2gz)(1 + √2gz) - (g + z)(g - z)

So, the correct answer is:

(1 - √2gz)(1 + √2gz)