Question

Даны векторы: а(2;0;-3), в(-3;-1;2).Найдите 3а-в.​

Answer 1

$\vec{a}(2;0;-3)\; \; ,\; \; \vec{b}=(-3;-1;2)\\\\3\vec{a}=(6;0;-9)\; \; ,\; \; -\vec{b}=(3;1;-2)\\\\3\vec{a}-\vec{b}=3\vec{a}+(-\vec{b})=(6+3;0+1;-9-2)=(9;1;-11)$

Answer 2

To find the vector 3a - v, we need to perform scalar multiplication and vector subtraction. First, let's find the value of 3a:

3a = 3 * (2, 0, -3) = (32, 30, 3*(-3)) = (6, 0, -9)

Next, we'll perform the vector subtraction:

3a - v = (6, 0, -9) - (-3, -1, 2) = (6 + 3, 0 + 1, -9 - 2) = (9, 1, -11)

So, the vector 3a - v is (9, 1, -11).