Question

5)3х²-5х-4=06)х²-24х=07)16х²-4=08)5х²=0​

Answer 1

Ответ:

Объяснение:

5) D= 25+48=73

x1= (5+√73)/6

x2= (5-√73)/6

6) x(x-24)=0

x1= 0

x2= 24

7) 4(4x²-1)=0

x1= -1/2

x2= 1/2

8) x=0

Answer 2

It looks like you've provided a set of quadratic equations. I'll go ahead and solve each of them for the variable "x."

5. 3x² - 5x - 4 = 0: To solve this quadratic equation, you can use the quadratic formula: x = (-b ± √(b² - 4ac)) / 2a

In this equation, a = 3, b = -5, and c = -4.

x = (-(-5) ± √((-5)² - 4 * 3 * -4)) / (2 * 3) x = (5 ± √(25 + 48)) / 6 x = (5 ± √73) / 6

So, the solutions are: x = (5 + √73) / 6 x = (5 - √73) / 6

6. x² - 24x = 0: Factor out x from the equation: x(x - 24) = 0

So, the solutions are: x = 0 x = 24

7. 16x² - 4 = 0: Factor out the common term: 4(4x² - 1) = 0

Now, solve for x: 4x² - 1 = 0 4x² = 1 x² = 1/4 x = ±√(1/4) x = ±1/2

So, the solutions are: x = 1/2 x = -1/2

8. 5x² = 0: Divide both sides by 5: x² = 0 x = ±√0 x = 0

So, the solution is: x = 0

These are the solutions for the given quadratic equations.