Question

(2x+1)(x-3)-(1-x)(x+5)=29-11x​

Answer 1

Объяснение:

все очень подробно на фотографиях

Answer 2

Let's simplify the given expression step by step:

Given expression: (2x+1)(x-3) - (1-x)(x+5) = 29 - 11x

Expand the expressions: (2x+1)(x-3) = 2x(x) + 2x(-3) + 1(x) + 1(-3) = 2x^2 - 6x + x - 3 = 2x^2 - 5x - 3

(1-x)(x+5) = 1(x) + 1(5) - x(x) - x(5) = x + 5 - x^2 - 5x = -x^2 - 4x + 5

Now substitute the expanded expressions back into the main equation: (2x^2 - 5x - 3) - (-x^2 - 4x + 5) = 29 - 11x

Simplify the equation further: 2x^2 - 5x - 3 + x^2 + 4x - 5 = 29 - 11x

Combine like terms: 3x^2 - x - 8 = 29 - 11x

Move all terms to one side of the equation: 3x^2 + 10x - 37 = 0

This is a quadratic equation in the form of ax^2 + bx + c = 0, where a = 3, b = 10, and c = -37.

You can solve this quadratic equation using the quadratic formula: x = (-b ± √(b^2 - 4ac)) / 2a

Plugging in the values: x = (-10 ± √(10^2 - 4 * 3 * -37)) / (2 * 3) x = (-10 ± √(100 + 444)) / 6 x = (-10 ± √544) / 6 x = (-10 ± 4√34) / 6

So, the solutions for the quadratic equation are: x = (-10 + 4√34) / 6 x = (-10 - 4√34) / 6

These are the simplified solutions for the given equation.