Question

1)3x-x²=0 2)y²+y=0 3)11x²-x=0 4)9x²+6x=0

Answer 1

Ответ:

1) x(3-x)=0

X1=3

X2=0

2) y(y+1)=0

y1= -1

y2=0

3) x(11x-1)=0

X1=1:11 (дробью)

X2=0

4) 3x(3x+2)=0

X1= -2:3 (дробью)

X2=0

Answer 2

To solve each of these quadratic equations, we'll use different methods depending on the equation. Let's solve them one by one:

1. 3x - x² = 0

To solve this quadratic equation, we can factor it:

x(3 - x) = 0

Now, set each factor equal to zero and solve for x:

1st factor: x = 0 2nd factor: 3 - x = 0 -x = -3 x = 3

So, the solutions to the equation are x = 0 and x = 3.

2. y² + y = 0

To solve this quadratic equation, we can factor it:

y(y + 1) = 0

Now, set each factor equal to zero and solve for y:

1st factor: y = 0 2nd factor: y + 1 = 0 y = -1

So, the solutions to the equation are y = 0 and y = -1.

3. 11x² - x = 0

To solve this quadratic equation, we can factor it:

x(11x - 1) = 0

Now, set each factor equal to zero and solve for x:

1st factor: x = 0 2nd factor: 11x - 1 = 0 11x = 1 x = 1/11

So, the solutions to the equation are x = 0 and x = 1/11.

4. 9x² + 6x = 0

To solve this quadratic equation, we can factor out the common factor, which is 3x:

3x(3x + 2) = 0

Now, set each factor equal to zero and solve for x:

1st factor: 3x = 0 x = 0 2nd factor: 3x + 2 = 0 3x = -2 x = -2/3

So, the solutions to the equation are x = 0 and x = -2/3.