Question

2) sin270° + 3tg180°;​

Answer 1

sin270+3tg180=sin(180+90)+3tg180=sin(pi+pi/2)+3tg(pi)=sin(3pi/2)+3tg(pi)=-1+0=-1

Answer 2

Let's calculate the values of sin(270°) and tan(180°) step by step:

1. sin(270°): The sine function has a period of 360 degrees, which means that sin(x) = sin(x + 360°) for any angle x. Therefore, we can find an equivalent angle within one period:

   270° is 360° - 90°, so sin(270°) = sin(360° - 90°).

   Now, we know that sin(360°) = 0° because it's a full rotation, and sin(90°) = 1, so sin(270°) = sin(360° - 90°) = sin(360°) * sin(90°) = 0 * 1 = 0.

2. tan(180°): The tangent function also has a period of 180 degrees, which means that tan(x) = tan(x + 180°) for any angle x. Therefore, we can find an equivalent angle within one period:

   180° is a half-rotation, so tan(180°) = tan(0°) because tan(0°) is also 0.

Now, let's calculate the expression:

sin(270°) + 3tan(180°) = 0 + 3 * 0 = 0.

So, the value of the expression is 0.