Question

1)(2a+3)²2)(5+4b)4b-5)​

Answer 1

Ответ:

1) (2а+3)^2=(2а+3)(2а+3)=4а^2+6а+6а+9=4а^2+12а+9

2) (5+4b)(5+4b)=20b-25+16b^2-20b= -25+16b^2

Объяснение:

Answer 2

It seems like you want to expand two algebraic expressions. Let's expand both of them:

1. (2a + 3)²:

To expand the square of a binomial, you can use the FOIL method (First, Outer, Inner, Last) or simply apply the formula (a + b)² = a² + 2ab + b². In this case, a = 2a and b = 3.

(2a + 3)² = (2a)² + 2(2a)(3) + (3)² = 4a² + 12a + 9

So, the expanded form of (2a + 3)² is 4a² + 12a + 9.

2. (5 + 4b)(4b - 5):

To expand this expression, you can also use the FOIL method:

(5 + 4b)(4b - 5) = 5 * 4b + 5 * (-5) + 4b * 4b + 4b * (-5)

Now, calculate each term:

= 20b - 25 + 16b² - 20b

Combine like terms:

= 20b - 20b - 25 + 16b²

Since the terms "20b" and "-20b" cancel each other out, you are left with:

= 16b² - 25

So, the expanded form of (5 + 4b)(4b - 5) is 16b² - 25.