Question

 (х-1)(х+1)-(х-2)(х+3)=4​

Answer 1

Відповідь:

1

Пояснення:

$x^{2} -1-x^{2} -3x+2x+6=4$

$x^{2} -1-x^{2} -3x+2x+6=4$

x=1

Answer 2

Let's solve the equation step by step:

(х-1)(х+1) - (х-2)(х+3) = 4

First, we'll expand the expressions:

(x^2 - 1) - (x^2 - 2x - 3x - 6) = 4

Now, combine like terms:

x^2 - 1 - (x^2 - 5x - 6) = 4

Next, distribute the negative sign to both terms inside the parentheses:

x^2 - 1 - x^2 + 5x + 6 = 4

Now, simplify further by canceling out the x^2 terms:

-1 + 5x + 6 = 4

Combine the constants on the left side:

5x + 5 = 4

Subtract 5 from both sides to isolate the variable:

5x = 4 - 5 5x = -1

Now, divide both sides by 5 to solve for x:

x = -1/5

So, the solution to the equation is:

x = -1/5