Question

25у²-10уz+z²+10y-2z=​

Answer 1

35у’3-10уz+3z’3
Всё что смогла

Answer 2

The expression you've provided is a quadratic equation in terms of the variables y and z:

25y² - 10yz + z² + 10y - 2z = 0

This quadratic equation can be written in standard form as:

25y² + (-10z + 10)y + (z² - 2z) = 0

To solve this quadratic equation for y (or z, if you prefer), you can use the quadratic formula:

y = (-b ± √(b² - 4ac)) / (2a)

In this case, a = 25, b = -10z + 10, and c = z² - 2z. Plugging these values into the quadratic formula will give you the solutions for y in terms of z:

y = [-(10z - 10) ± √((10z - 10)² - 4(25)(z² - 2z))] / (2(25))

Simplify and solve for y:

y = [-(10z - 10) ± √(100z² - 400z + 100 - 100z² + 200z)] / 50

y = [-(10z - 10) ± √(100 - 400z + 200z)] / 50

y = [-(10z - 10) ± √(100 - 200z)] / 50

y = [-(10z - 10) ± √(100(1 - 2z))] / 50

Now, you can simplify further:

y = [-10z + 10 ± 10√(1 - 2z)] / 50

y = (-2z + 2 ± √(1 - 2z)) / 5

So, the solutions for y in terms of z are:

1. y = (-2z + 2 + √(1 - 2z)) / 5
2. y = (-2z + 2 - √(1 - 2z)) / 5