Question

³√a³ ³√b⁹/a-² 1)-a²b 2)-ab 3)a²b 4)a²b 5)a²b² 6)ab²

Answer 1

Ответ:

В объяснении.

Объяснение:

$\sqrt[3]{a {}^{3} } \times \frac{ \sqrt[3]{b {}^{9} } }{a {}^{ - 2} } = a \times \frac{b {}^{3} }{a {}^{ - 2} } = a {}^{3} b {}^{3}$

Answer 2

To simplify the expression $\sqrt[3]{a^3} \cdot \sqrt[3]{b^9} / (a^{-2})$, you can use the properties of exponents and the rules of radicals:

1. $\sqrt[3]{a^3}$ simplifies to $a$ because the cube root of $a^3$ is $a$.
2. $\sqrt[3]{b^9}$ simplifies to $b^3$ because the cube root of $b^9$ is $b^3$.
3. $a^{-2}$ is the same as $\frac{1}{a^2}$.

Now, the expression becomes:

$a \cdot b^3 / \frac{1}{a^2}$

To simplify this further, you can multiply $a$ and $b^3$ in the numerator and divide by $\frac{1}{a^2}$, which is the same as multiplying by $a^2$:

$ab^3 \cdot a^2$

Using the properties of exponents, you can simplify this expression as:

$a^{1+2} \cdot b^3$

$a^3 \cdot b^3$

So, the simplified expression is $a^3b^3$.

None of the options provided matches this result. Please check the expression and options again.