Question

Срочно решите пожалуйста № 10 У дорожки стоит столб. Улитки Фрося, Муся и Кузя одновременно поползли от основания столба с постоянными скоростями, Фрося - направо по дорожке, Муся -- налево по дорожке, а Кузя -- вверх по столбу. Скорость улитки Кузи на 2 см в минуту меньше скорости улитки Фроси, а скорость улитки Муси вдвое больше скорости улитки Кузи. Через час между Мусей и Фросей было 6 м 60 см. На какую высоту за этот час заполз Кузя? Ответ выразите в сантиметрах. Число или дробь

Answer 1

Объяснение:

6 м 60 см=660 см.

Пусть скорость Кузи - х см/мин.        ⇒

Скорость Фроси - (х+2) см/мин.

Скорость Муси - (2х) см/мин.        

(х+2)*60+2х*60=660 |:60

x+2+2x=11

3x=9 |:3

x=3 (см/мин)

h=3*60=180 (см).

Ответ: Кузя за этот час заполз на высоту 180 см.

Answer 2

Problem Analysis

We are given that three snails, Frose, Musya, and Kuzia, start crawling simultaneously from the base of a pole. Frose crawls to the right along a track, Musya crawls to the left along the same track, and Kuzia crawls upward along the pole. We are also given the following information: - Kuzia's speed is 2 cm per minute slower than Frose's speed. - Musya's speed is twice as fast as Kuzia's speed. - After one hour, there is a distance of 6 meters and 60 centimeters between Musya and Frose.

We need to determine how high Kuzia crawled in that hour.

Solution

Let's assume that Frose's speed is x cm per minute. Therefore, Kuzia's speed is (x - 2) cm per minute, and Musya's speed is 2(x - 2) cm per minute.

We know that the distance between Musya and Frose after one hour is 6 meters and 60 centimeters, which is equal to 660 centimeters.

To find Kuzia's height, we need to calculate the distance each snail traveled in one hour.

- Frose's distance: x cm/min * 60 min = 60x cm - Musya's distance: 2(x - 2) cm/min * 60 min = 120(x - 2) cm

The total distance between Musya and Frose is the sum of their distances:

60x cm + 120(x - 2) cm = 660 cm

Now, we can solve this equation to find the value of x and then calculate Kuzia's height.

Solving the Equation

Let's solve the equation step by step:

60x cm + 120(x - 2) cm = 660 cm

First, distribute the 120:

60x cm + 120x cm - 240 cm = 660 cm

Combine like terms:

180x cm - 240 cm = 660 cm

Add 240 cm to both sides:

180x cm = 900 cm

Divide both sides by 180:

x = 5 cm/min

Now that we have the value of x, we can calculate Kuzia's height.

Kuzia's speed is (x - 2) = (5 - 2) = 3 cm/min.

In one hour, Kuzia crawled 3 cm/min * 60 min = 180 cm.

Therefore, Kuzia crawled to a height of 180 cm in that hour.

Answer

Kuzia crawled to a height of 180 cm in one hour.

Note: The answer is expressed in centimeters.