Question

срочно дам 30 балов Температура нагрівника ідеальної теплової машини дорівнює 147 °С, а температура холодильника становить 7 °С. ККД цієї теплової машини дорівнює приблизно

Answer 1

Ответ:

95 %

Объяснение:

Answer 2

The efficiency of an ideal heat engine can be calculated using the Carnot efficiency formula. The Carnot efficiency (η) is given by the equation:

η = 1 - (Tc/Th)

Where: - η is the efficiency of the heat engine, - Tc is the temperature of the cold reservoir (in Kelvin), - Th is the temperature of the hot reservoir (in Kelvin).

In this case, the temperature of the hot reservoir (nagrivnik) is given as 147 °C, which is equivalent to 147 + 273 = 420 K. The temperature of the cold reservoir (holodilnik) is given as 7 °C, which is equivalent to 7 + 273 = 280 K.

Now, let's calculate the efficiency of this heat engine using the Carnot efficiency formula:

η = 1 - (280/420) = 1 - 0.6667 = 0.3333

Therefore, the efficiency of this heat engine is approximately 0.3333 or 33.33%.

Please note that this calculation assumes that the heat engine is an ideal heat engine, which means it operates under ideal conditions without any losses or inefficiencies. In reality, no heat engine can achieve 100% efficiency due to various factors such as friction, heat losses, and other inefficiencies.