Question

Q1=90нКл q2=10нКл r=4см r1,r2=?

Answer 1

Ответ: 3см

Объяснение:

k*q1*q3/R1^2=k*q2*q3/(R-R1)^2;

q1/q2=R1^2/(R-R1)^2;

R1/(R-R1)=(q1/q2)^(1/2);

R-R1=R1*(q2/q1)^(1/2);

R=R1(1+(q2/q1)^(1/2));

R1=R/(1+(q2/q1)^(1/2));

R1=0,04/(1+(1/9)^(1/2))=4/(40/3)=0,03 м=3 см.

Answer 2

To calculate the values of r1 and r2, we can use Coulomb's law, which describes the electrostatic force between two point charges. Coulomb's law is given by:

$F = \frac{k \cdot |q1 \cdot q2|}{r^2}$

where:

• F is the electrostatic force between the charges q1 and q2,
• k is Coulomb's constant ($k \approx 8.99 \times 10^9 \, \text{N m}^2/\text{C}^2$ in SI units),
• $q1$ and $q2$ are the magnitudes of the point charges in coulombs, and
• $r$ is the distance between the two charges in meters.

Given the values: $q1 = 90 \, \text{нКл}$ (nano-coulombs = $90 \times 10^{-9}$ coulombs), $q2 = 10 \, \text{нКл}$ (nano-coulombs = $10 \times 10^{-9}$ coulombs), $r = 4 \, \text{см}$ (centimeters = $4 \times 10^{-2}$ meters).

We need to convert the distances to meters before calculating the force. So, $r = 4 \times 10^{-2} \, \text{m}$.

Now, let's calculate the electrostatic force (F):

$F = \frac{(8.99 \times 10^9 \, \text{N m}^2/\text{C}^2) \cdot |(90 \times 10^{-9} \, \text{C}) \cdot (10 \times 10^{-9} \, \text{C})|}{(4 \times 10^{-2} \, \text{m})^2}$

$F = \frac{8.99 \times 10^9 \times 90 \times 10^{-9} \times 10 \times 10^{-9}}{16 \times 10^{-4}}$

$F = \frac{8.99 \times 90 \times 10^{10}}{16}$

$F = \frac{809.1 \times 10^{10}}{16}$

$F = 50568.75 \, \text{N}$

Now, we know the force between the charges, and we can use this information to calculate the distances $r1$ and $r2$.

The distances $r1$ and $r2$ are the distances from each charge to the point where the net electrostatic force is zero. This occurs when both forces are equal in magnitude but opposite in direction.

Since the force is inversely proportional to the square of the distance (F = k * |q1 * q2| / r^2), the sum of the distances from each charge to the point where the net force is zero is equal to the separation distance (r) between the two charges. Therefore:

$r = r1 + r2$

Solving for $r1$:

$r1 = r - r2$

Now, since we know $r = 4 \times 10^{-2} \, \text{m}$ and $F = 50568.75 \, \text{N}$, we can calculate $r1$.

$4 \times 10^{-2} = r1 + r2$

$r1 = 4 \times 10^{-2} - r2$

At this point, we need additional information or an additional equation to solve for both $r1$ and $r2$ separately. If you have any other relevant information or equations related to the problem, please provide them, and I'll be happy to help you further.