Question

Капля ртути имевшая заряд 3q слилась с другой каплей с зарядом -2q.Заряд вновь образовавшейся капли равен ...1) -5q 2) +5q 3) +q 4) -q Капля масла с зарядом -6нКл соединилась с каплей,заряд которой +4 нКл.Каким стал заряд объединенной капли? 1) -10нКл 2) 10нКл 3) +2нКл 4) -2нКл

Answer 1

3q+(-2q) = q  ответ: (3)
- 6нКл+4нКл = -2нКл Ответ: (4)

Answer 2

Calculation of Charge in the New Droplet

When a droplet of mercury with a charge of 3q combines with another droplet with a charge of -2q, the charges add up. The resulting charge in the new droplet can be calculated by adding the charges of the two droplets together.

Let's calculate the charge in the new droplet:

Charge of the first droplet = 3q Charge of the second droplet = -2q

To find the charge in the new droplet, we add the charges together:

3q + (-2q) = q

Therefore, the charge in the new droplet is q.

Calculation of Charge in the Combined Droplet

When a droplet of oil with a charge of -6nC (nanocoulombs) combines with another droplet with a charge of +4nC, the charges add up. The resulting charge in the combined droplet can be calculated by adding the charges of the two droplets together.

Let's calculate the charge in the combined droplet:

Charge of the first droplet = -6nC Charge of the second droplet = +4nC

To find the charge in the combined droplet, we add the charges together:

-6nC + 4nC = -2nC

Therefore, the charge in the combined droplet is -2nC.

So, the answer to the question "Каким стал заряд объединенной капли?" (What is the charge of the combined droplet?) is -2нКл (option 4).