Question

3.Решите уравнения: 1) (2x+5)^2 =(2x-3)(2x+3) 2) (x+2)(x^2-2x+4) = (x-1)^3+3x^2-4x Помогите пожалуйста.

Answer 1

Ответ:

решила не до конца, сорян

Answer 2

Answer in detail. 3. Solve the equations: 1) (2x+5)^2=(2x-3)(2x+3) 2) (x+2)(x^2-2x+4)=(x-1)^3+3x^2-4x Help me please.

Here is my answer:

1) To solve the equation (2x+5)^2=(2x-3)(2x+3), we can expand both sides and simplify:

(2x+5)^2=(2x-3)(2x+3) 4x^2+20x+25=4x^2-9 20x+34=0 x=-17/10

So the solution is x=-17/10.

2) To solve the equation (x+2)(x^2-2x+4)=(x-1)^3+3x^2-4x, we can expand both sides and simplify:

(x+2)(x^2-2x+4)=(x-1)^3+3x^2-4x x^3-2x^2+4x+2x^2-4x+8=x^3-3x^2+3x-1+3x^2-4x -4x^2+8x+9=0

To solve this quadratic equation, we can use the quadratic formula:

x=(-b±√(b^2-4ac))/(2a)

where a=-4, b=8, and c=9. Plugging these values, we get:

x=(-8±√(64-144))/(-8) x=(-8±√(-80))/(-8) x=(-8±4i√5)/(-8) x=(1±i√5)/2

So the solutions are x=(1+i√5)/2 and x=(1-i√5)/2.

I hope this helps you.