Question

2. Представ вираз у вигляді добутку многочленів. а) 6m(p – 3) + 5n(p – 3);б) 7qр — q) – 2(р – q);В) 3-а+ 2(3 - а);г) 5x(x+y) +x+y.помогите срочно​

Answer 1

A) (p-3) (6m+5n)
Б) (p-q) (7q-2)
В) (3-а) (1+2)
Г) (х +у) (5х+1)

Answer 2

a) 6m(p+–+3)+++5n(p+–+3)

To express the given expression as a product of polynomials, let's simplify it step by step:

1. Distribute the first term, 6m, to both terms inside the parentheses: 6m(p + –3)

2. Distribute the second term, 5n, to both terms inside the parentheses: 5n(p + –3)

Now, we can see that both terms have a common factor of (p + –3). We can factor it out:

(p + –3)(6m + 5n)

So, the expression 6m(p+–+3) + 5n(p+–+3) can be expressed as the product of the polynomials (p + –3) and (6m + 5n).

b) 7qр + q + –2(р + –q)

To express the given expression as a product of polynomials, let's simplify it step by step:

1. Distribute the -2 to both terms inside the parentheses: -2(р + –q) = -2р + 2q

Now, we can see that the expression has a common factor of (q + –2р). We can factor it out:

(q + –2р)(7 + 1)

So, the expression 7qр + q + –2(р + –q) can be expressed as the product of the polynomials (q + –2р) and (7 + 1).

c) 3-а + 2(3 + –а)

To express the given expression as a product of polynomials, let's simplify it step by step:

1. Distribute the 2 to both terms inside the parentheses: 2(3 + –а) = 6 + –2а

Now, we can see that the expression has a common factor of (3 + –2а). We can factor it out:

(3 + –2а)(1)

So, the expression 3-а + 2(3 + –а) can be expressed as the product of the polynomials (3 + –2а) and (1).

г) 5x(x + y) + x + y

To express the given expression as a product of polynomials, let's simplify it step by step:

1. Distribute the 5x to both terms inside the parentheses: 5x(x + y) = 5x^2 + 5xy

Now, we can see that the expression has a common factor of (x + y). We can factor it out:

(x + y)(5x + 1)

So, the expression 5x(x + y) + x + y can be expressed as the product of the polynomials (x + y) and (5x + 1).

I hope this helps! Let me know if you have any further questions.