Question

Дам 20 баллов. (2 задания) №1 (Расставить в порядке возрастания) Нужно решение -3√5 ; -4√3 ; -2√11 №2 (Решите по действиям) (4√3 - 2√5) • √3 + √60 =

Answer 1

1

все надо внести под корень и потом сравнивать

-3√5 = - √5*9 = -√45

-4√3 = -√3*16 = -√48

-2√11 = - √11*4 = -√44

в порядке возрастания

- √48, -√45, -√44

2.

(4√3 - 2√5)*√3 + √60 = 4√3*√3 - 2√5*√3 + √60 = 4(√3)² - √4*15 + √60 = 4*3 - √60 + √60 = 12

Answer 2

Ответ:№1 -4√3, -3√5, -2√11 №2

Объяснение: №1 -3√5=-√45,  -4√3=-√46, -2√11=-√44, -√46 меньше -√45 меньше -√44

№2 (4√3 - 2√5) • √3 + √60 = 4√3• √3-2√5•√3 + √60=4√3•3-2√5•3+ √60=4√9-2√15+ √60=4•3-2√15+ √60=12-√60+60=12-√60+60=12

Answer 3

Task 1: Sorting in Ascending Order

To solve the task of sorting the given numbers in ascending order, we can use the square root (√) and the negative sign (-) to represent the numbers. Here is the solution:

-3√5, -4√3, -2√11

Let's break down the solution step by step:

1. Start with the given numbers: -3√5, -4√3, -2√11. 2. Calculate the square root of each number: √5 ≈ 2.236, √3 ≈ 1.732, √11 ≈ 3.317. 3. Apply the negative sign to each square root: -2.236, -1.732, -3.317. 4. Arrange the numbers in ascending order: -3.317, -2.236, -1.732.

Therefore, the numbers in ascending order are: -3√5, -4√3, -2√11.

Note: The approximate values of the square roots are rounded for simplicity.

Task 2: Simplifying an Expression

The expression to simplify is: (4√3 - 2√5) • √3 + √60.

Let's break down the solution step by step:

1. Simplify the expression inside the parentheses: 4√3 - 2√5. 2. Multiply each term inside the parentheses by √3: (4√3 • √3) - (2√5 • √3). - Simplify the multiplication: 4 • 3 - 2√15. - Calculate: 12 - 2√15. 3. Simplify the expression outside the parentheses: (12 - 2√15) + √60. 4. Simplify the square root of 60: √60 ≈ 7.746. 5. Add the simplified expressions: 12 - 2√15 + 7.746. 6. Combine like terms: 12 + 7.746 - 2√15. 7. Calculate the sum: 19.746 - 2√15.

Therefore, the simplified expression is: 19.746 - 2√15.

I hope this helps! Let me know if you have any further questions.