Question

12x^2+16x-3=0 pleassseeee​

Answer 1

Ответ:

x1= 1/6

x2= -3/2

Объяснение:

12x^2+16x-3=0

D=b^2-4ac=256+144=400

x1= (-b+√d)/2a= (-16+20)/24= 1/6

x2= (-b-√d)/2a= (-16-20)/24= -3/2

Answer 2

To solve the quadratic equation 12x^2 + 16x - 3 = 0, you can use the quadratic formula:

x = (-b ± √(b² - 4ac)) / (2a)

In this equation, a = 12, b = 16, and c = -3. Plug these values into the formula:

x = (-16 ± √(16² - 4 * 12 * (-3))) / (2 * 12)

Now, calculate the discriminant (the value inside the square root):

Discriminant (D) = b² - 4ac D = 16² - 4 * 12 * (-3) D = 256 + 144 D = 400

Now, substitute the discriminant and the values of a, b, and c back into the quadratic formula:

x = (-16 ± √400) / (2 * 12)

Simplify the square root:

x = (-16 ± 20) / 24

Now, you have two possible solutions:

1. x = (-16 + 20) / 24 x = 4 / 24 x = 1/6

2. x = (-16 - 20) / 24 x = -36 / 24 x = -3/2

So, the solutions for the equation 12x^2 + 16x - 3 = 0 are x = 1/6 and x = -3/2.