Question

7b(2b+3)-(b+6)(b-5)=14b²+21b-(b²-5b+6b-30)=14b²+21b-b²+5b-6b+30=13b²+20b+30=13b²+10(2b+3) Подскажите, как получилось 13b²+10(2b+3)? не понимаю..

Answer 1

Объяснение:

сначала собираем подобные 14 b квадрат отняли 1 b квадрат 21 b прибавили 5 b и отняли 6 b потом получилось 13b квадрат и 20 b, и 30 затем 10 вынесли за скобкой и получилось так

Answer 2

To solve the equation 7b(2b+3)-(b+6)(b-5)=14b²+21b-(b²-5b+6b-30)=14b²+21b-b²+5b-6b+30=13b²+20b+30=13b²+10(2b+3), let's break it down step by step:

1. Start with the given equation: 7b(2b+3)-(b+6)(b-5)=14b²+21b-(b²-5b+6b-30).

2. Simplify the equation by applying the distributive property. Multiply 7b by 2b and 7b by 3, and multiply (b+6) by (b-5): - 7b(2b+3) = 14b² + 21b - (b+6)(b-5) = b² - 5b + 6b - 30 = b² + b - 30

3. Substitute the simplified expressions back into the original equation: 14b² + 21b - (b² + b - 30) = 14b² + 21b - b² - b + 30

4. Combine like terms: 14b² + 21b - b² - b + 30 = 13b² + 20b + 30

5. The equation simplifies to 13b² + 20b + 30.

Regarding the expression 13b² + 10(2b+3), it can be simplified by applying the distributive property: 13b² + 10(2b+3) = 13b² + 10(2b) + 10(3) = 13b² + 20b + 30.

Therefore, the expression 13b² + 10(2b+3) is equivalent to the simplified form of the given equation, 13b² + 20b + 30.

I hope this explanation helps! Let me know if you have any further questions.