Question

1. x² - 4x+3=0   2.x² +3x-10=0

Answer 1

1). X=(4+2):2=1
X=(4-2):2=3
2). X=-10/2=-5
X=4/2=2

Answer 2

1)x² - 4x+3=0
D=b²-4ac=(-4)²-4*1-3=16-12=4
х= -b+√D:2а= 4+2:2=3
х1=3, 
х= -b-√D=4-2:2=1
х2=1
2).x² +3x-10=0
D=b²-4ac=3²-4*1*(-10)=9-40=49
х= -b+√D:2а=-3+7:2=2
х1=2
х= -b-√D:2а=-3-7:2=-5
х2=-5

Answer 3

To solve these quadratic equations, you can use the quadratic formula:

For a quadratic equation in the form ax² + bx + c = 0, the quadratic formula is:

x = (-b ± √(b² - 4ac)) / (2a)

Let's apply this formula to your two equations:

1. x² - 4x + 3 = 0 In this equation, a = 1, b = -4, and c = 3. Plugging these values into the quadratic formula:

   x = (4 ± √((-4)² - 4(1)(3))) / (2(1))

   x = (4 ± √(16 - 12)) / 2

   x = (4 ± √4) / 2

   x = (4 ± 2) / 2

   Now, you have two possible solutions:

   x₁ = (4 + 2) / 2 = 6 / 2 = 3 x₂ = (4 - 2) / 2 = 2 / 2 = 1

   So, the solutions to the first equation are x = 3 and x = 1.

2. x² + 3x - 10 = 0 In this equation, a = 1, b = 3, and c = -10. Plugging these values into the quadratic formula:

   x = (-3 ± √(3² - 4(1)(-10))) / (2(1))

   x = (-3 ± √(9 + 40)) / 2

   x = (-3 ± √49) / 2

   x = (-3 ± 7) / 2

   Now, you have two possible solutions:

   x₁ = (-3 + 7) / 2 = 4 / 2 = 2 x₂ = (-3 - 7) / 2 = -10 / 2 = -5

   So, the solutions to the second equation are x = 2 and x = -5.