Question

125-b3=27a6+b9=(a2+4b)2=(3a-2)2=4a2c2-9x6=5d6c4-8x9=​

Answer 1

Ответ:

1)(5-b)(25+5b+b2(квадрат)

2.(3a2+b3)(9a4-3a2b3+b6)

3.2a2 + 8b

4.6a-4

5.2(2a2c2-27)

6.5c4d6 - 72

Answer 2

It appears you've provided a series of equations, and I'm not sure what you would like me to do with them. Please clarify your question or provide more information about what you need assistance with regarding these equations.