Question

1) 2х + 3 = - 17; 2) 5( 3у - 2) = 17; 3) 3,1( х+ 7) = х + 25,9.

Answer 1

Объяснение:

1)

$2x + 3 = - 17 \\ 2x = - 17 - 3 \\ 2x = - 20 \\ x = - 10$

2)

$5(3y - 2) = 17 \\ 15y - 10 = 17 \\ 15y = 17 + 10 \\ 15y = 27 \\ y = \frac{9}{5} = 1 \frac{4}{5} = 1.8$

3)

$3.1(x + 7) = x + 25.9 \\ 3.1x + 21.7 = x + 25.9 \\ 3.1x - x = 25.9 - 21.7 \\ 2.1x = 25.9 - 21.7 \\ 21.x = 4.2 \\ x = 2$

Answer 2

Ответ:

1)2х+3=-17

2х=-17-3

2х=-20

х=-20:2

х=10

2)5(3у-2)=17

15у-10=17

15у=17+10

15у=27

у=15:27

у=1,8

3)3,1(х+7)=х+25,9

3,1х + 21,7=х+25,9

3,1х-х=25,9-21,7

3х=4,2

х=4,2:3=1,4

Answer 3

Let's solve each equation step by step:

1. $2x + 3 = -17$

Subtract 3 from both sides:

$2x = -20$

Divide both sides by 2:

$x = -10$

So, the solution to the first equation is $x = -10$.

2. $5(3y - 2) = 17$

Distribute the 5 on the left side:

$15y - 10 = 17$

Add 10 to both sides:

$15y = 27$

Divide both sides by 15:

$y = \frac{27}{15} = \frac{9}{5}$

So, the solution to the second equation is $y = \frac{9}{5}$.

3. $3.1(x + 7) = x + 25.9$

Distribute the 3.1 on the left side:

$3.1x + 21.7 = x + 25.9$

Subtract x from both sides:

$2.1x + 21.7 = 25.9$

Subtract 21.7 from both sides:

$2.1x = 4.2$

Divide both sides by 2.1:

$x = \frac{4.2}{2.1} = 2$

So, the solution to the third equation is $x = 2$.