Question

Решите уравнения а) (х-3)(2х+6)=0 б) |3х-1|=2х+1 в) х-4,1/2,5=х+0,8/5

Answer 1

Ответ:

а) -1

б) 0

в) -2/33

Объяснение:

..............................

Answer 2

a) (x-3)(2x+6) = 0:

1. Set each factor equal to zero and solve for x:

x - 3 = 0 2x + 6 = 0

2. Solve each equation separately:

For x - 3 = 0: x = 3

For 2x + 6 = 0: 2x = -6 x = -3

So, the solutions are x = 3 and x = -3.

b) |3x-1| = 2x+1:

1. Consider two cases, one where the absolute value is positive and one where it's negative.

Case 1 (Positive Absolute Value):

3x - 1 = 2x + 1

2. Solve for x:

3x - 2x = 1 + 1 x = 2

Case 2 (Negative Absolute Value):

-(3x - 1) = 2x + 1

2. Solve for x:

-3x + 1 = 2x + 1

Add 3x to both sides:

1 = 5x + 1

Subtract 1 from both sides:

0 = 5x

Now, divide by 5:

x = 0

So, the solutions are x = 0 and x = 2.

c) x - 4.1/2.5 = x + 0.8/5:

This equation doesn't have a unique solution because the variable x cancels out when you subtract x from both sides. Therefore, there are no real solutions to this equation. It's not possible to satisfy the equation as written.