Question

(5x-2)²-(4x-2)×2 (X²+4)²+5x(x²+4) 24x-18+(3x-12)² (3-x)²-(x+4)²

Answer 1

ОтветОтветОтветОтвет:

Объяснение

Answer 2

To simplify the expression $(5x-2)^2 - (4x-2) \times 2 + (x^2+4)^2 + 5x(x^2+4) + 24x-18 + (3x-12)^2 - (3-x)^2 - (x+4)^2$, you can follow these steps:

1. Expand each squared term:

   • $(5x-2)^2 = 25x^2 - 20x + 4$
   • $(x^2+4)^2 = x^4 + 8x^2 + 16$
   • $(3x-12)^2 = 9x^2 - 72x + 144$
   • $(3-x)^2 = 9 - 6x + x^2$

2. Distribute the constants:

   • $- (4x-2) \times 2 = -8x + 4$
   • $5x(x^2+4) = 5x^3 + 20x$
   • $- (x+4)^2 = -x^2 - 8x - 16$

Now, substitute these expanded expressions back into the original expression:

$$\begin{align*} & (25x^2 - 20x + 4) - (-8x + 4) + (x^4 + 8x^2 + 16) + (5x^3 + 20x) + 24x - 18 + (9x^2 - 72x + 144) - (9 - 6x + x^2) - (-x^2 - 8x - 16) \\ &= 25x^2 - 20x + 4 + 8x - 4 + x^4 + 8x^2 + 16 + 5x^3 + 20x + 24x - 18 + 9x^2 - 72x + 144 - 9 + 6x - x^2 + x^2 + 8x + 16 \\ &= x^4 + 10x^3 + 43x^2 - 22x + 127 \end{align*}$$

So, the simplified expression is $x^4 + 10x^3 + 43x^2 - 22x + 127$.