Question

(х+ 4)(4-х)+(х+5)х > 6х-20

Answer 1

Решение задания приложено

Answer 2

(4+x)×(4-x)-это формула
16-xв квадрате+xв квадрате+5x>6x-20
5x-6x>-20-16
-1x>-36
x<36

Answer 3

To solve the inequality $(x + 4)(4 - x) + (x + 5)x > 6x - 20$, follow these steps:

1. Expand and simplify the expressions on both sides of the inequality: $(x + 4)(4 - x) + (x + 5)x > 6x - 20$ \ $4x - x^2 + 16 - 4x + x^2 + 5x > 6x - 20$ \ $25x > 6x - 20$

2. Subtract $6x$ from both sides: $25x - 6x > -20$ \ $19x > -20$

3. Divide both sides by $19$ (remembering to flip the inequality sign when dividing by a negative number): $x > -\frac{20}{19}$

So, the solution to the inequality is $x > -\frac{20}{19}$.