Question

(b-4)(b+4) - (1+b)^2 при b= -1,5 помогите!!

Answer 1

Можно упростить немного, получим:
$b^2-16-1-2b-b^2 = -2b-17$

При b = -1,5 : 

$-2 * -1,5 - 17 = 3 - 17 = -14$

Answer 2

(b-4)(b+4)-(1+b)²=b²-16-(1+2b+b²)=b²-16-1-2b-b²=-17-2b.
Подставим значение b:
-17-2•(-1,5)=-17+3=-14.

Ответ: -14.

Answer 3

Sure, I'd be happy to help you with the expression (b-4)(b+4) - (1+b)^2 when b = -1.5.

First, let's plug in the value of b into the expression:

Step 1: Substitute b = -1.5

(b-4)(b+4) - (1+b)^2

= (-1.5 - 4)(-1.5 + 4) - (1 + (-1.5))^2

Step 2: Perform the operations inside the parentheses first:

= (-5.5)(2.5) - (1 - 1.5)^2

Step 3: Complete the operations in the parentheses:

= -13.75 - (-0.5)^2

Step 4: Square the value inside the parentheses:

= -13.75 - 0.25

Step 5: Perform the subtraction:

= -14

So, when b = -1.5, the expression (b-4)(b+4) - (1+b)^2 evaluates to -14.