Question

А)6x=30; б)5y=0; в)4z=-8; г)2x+3=19; ґ)3y-4=1; д)1-¾x=25

Answer 1

Ашнеуыгншегзщхзхзщшгнекуцу

Answer 2

Вот будто это вопросы ложь
Но я все таки написала.

Answer 3

To solve each of these equations, we'll isolate the variable on one side of the equation. Here are the solutions for each:

а) 6x = 30 Divide both sides by 6 to isolate x: x = 30 / 6 x = 5

б) 5y = 0 Divide both sides by 5 to isolate y: y = 0 / 5 y = 0

в) 4z = -8 Divide both sides by 4 to isolate z: z = -8 / 4 z = -2

г) 2x + 3 = 19 Subtract 3 from both sides to isolate 2x: 2x = 19 - 3 2x = 16 Now, divide both sides by 2 to find x: x = 16 / 2 x = 8

ґ) 3y - 4 = 1 Add 4 to both sides to isolate 3y: 3y = 1 + 4 3y = 5 Now, divide both sides by 3 to find y: y = 5 / 3

д) 1 - ¾x = 25 To get rid of the fraction, let's rewrite ¾ as 3/4: 1 - (3/4)x = 25 Subtract 1 from both sides to isolate -(3/4)x: -(3/4)x = 25 - 1 -(3/4)x = 24 Now, to solve for x, we need to isolate x, so we'll divide both sides by -(3/4): x = 24 / -(3/4) To divide by a fraction, we multiply by its reciprocal: x = 24 * (-4/3) x = -96 / 3 x = -32

So, the solutions are: а) x = 5 б) y = 0 в) z = -2 г) x = 8 ґ) y = 5/3 д) x = -32