Question

(-8)^0×(4×2^2)^2:8^2+1/6ab^2×12a при a=3 b=1/3

Answer 1

Помоги мннееееее пжжж пжжжж пжжж пжжж пжжж

Answer 2

Let's solve the expression step by step:

1. (-8)^0: Any non-zero number raised to the power of 0 is equal to 1. So, (-8)^0 = 1.

2. (4×2^2)^2: First, calculate the value inside the parentheses. 4×2^2 = 4×4 = 16. Now, raise 16 to the power of 2. (4×2^2)^2 = 16^2 = 256.

3. 8^2: 8 raised to the power of 2 is equal to 64.

4. Now, let's deal with the division: 1/6ab^2×12a

   Plug in the values of a and b: a = 3, b = 1/3

   1/6 * 3 * (1/3)^2 * 12 * 3

   Simplify the terms inside the parentheses: 1/6 * 3 * (1/9) * 12 * 3

   Now, perform the multiplication and division: 1/6 * 3 * 1/9 * 12 * 3 1/6 * 1/3 * 12 * 3 1/18 * 12 * 3 1/18 * 36 2

Now, let's put all the results together:

(-8)^0 × (4×2^2)^2 ÷ 8^2 + 1/6ab^2×12a

Substitute the results: 1 × 256 ÷ 64 + 2

Now, perform the remaining calculations: 256 ÷ 64 = 4 4 + 2 = 6

The final result is 6.